Solve {l}{62=34+4x}{y=x}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 62 = 34 + 4 x }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c=7$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$34+4x=62$$

Subtract 34 from both sides.

$$4x=62-34$$

Subtract 34 from 62 to get 28.

$$4x=28$$

Divide both sides by 4.

$$x=\frac{28}{4}$$

Divide 28 by 4 to get 7.

$$x=7$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=7$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=7$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=7$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=7$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=7$$

The system is now solved.

$$x=7 y=7 z=7 a=7 b=7 c=7$$