Solve {l}{60*x*10=300}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 60 \cdot x \cdot 10 = 300 }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=\frac{1}{2}=0.5$$

Solution Steps

Consider the first equation. Multiply 60 and 10 to get 600.

$$600x=300$$

Divide both sides by 600.

$$x=\frac{300}{600}$$

Reduce the fraction \frac{300}{600} to lowest terms by extracting and canceling out 300.

$$x=\frac{1}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{1}{2}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{1}{2}$$

The system is now solved.

$$x=\frac{1}{2} y=\frac{1}{2} z=\frac{1}{2}$$