Solve {l}{6z-0*2{(3z-9)}=-0*5{(2z+6)}}{a=2}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 6 z - 0 \cdot 2 {(3 z - 9)} = -0 \cdot 5 {(2 z + 6)} }\\ { a = 2 }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for z, a, b

$$b=2$$

Solution Steps

Consider the first equation. Multiply 0 and 2 to get 0.

$$6z-0\left(3z-9\right)=0\times 5\left(2z+6\right)$$

Anything times zero gives zero.

$$6z-0=0\times 5\left(2z+6\right)$$

Multiply 0 and 5 to get 0.

$$6z-0=0\left(2z+6\right)$$

Anything times zero gives zero.

$$6z-0=0$$

Add 0 to both sides.

$$6z=0+0$$

Add 0 and 0 to get 0.

$$6z=0$$

Divide both sides by 6. Zero divided by any non-zero number gives zero.

$$z=0$$

The system is now solved.

$$z=0 a=2 b=2$$