Solve {l}{6x=18}{y=x+0}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 6 x = 18 }\\ { y = x + 0 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=3$$

Solution Steps

Consider the first equation. Divide both sides by 6.

$$x=\frac{18}{6}$$

Divide 18 by 6 to get 3.

$$x=3$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=3+0$$

Add 3 and 0 to get 3.

$$y=3$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=3$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=3$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=3$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=3$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=3$$

The system is now solved.

$$x=3 y=3 z=3 a=3 b=3 c=3 d=3$$