Solve {l}{6x=0*3-3{(x-2*5)}}{y=0}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 6 x = 0 \cdot 3 - 3 {(x - 2 \cdot 5)} }\\ { y = 0 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=0$$

Solution Steps

Consider the first equation. Multiply 0 and 3 to get 0.

$$6x=0-3\left(x-2\times 5\right)$$

Multiply 2 and 5 to get 10.

$$6x=0-3\left(x-10\right)$$

Use the distributive property to multiply -3 by x-10.

$$6x=0-3x+30$$

Add 0 and 30 to get 30.

$$6x=30-3x$$

Add 3x to both sides.

$$6x+3x=30$$

Combine 6x and 3x to get 9x.

$$9x=30$$

Divide both sides by 9.

$$x=\frac{30}{9}$$

Reduce the fraction \frac{30}{9} to lowest terms by extracting and canceling out 3.

$$x=\frac{10}{3}$$

The system is now solved.

$$x=\frac{10}{3} y=0 z=0 a=0 b=0 c=0 d=0$$