Solve {l}{6x+9=0}{y=x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 6 x + 9 = 0 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b = -\frac{3}{2} = -1\frac{1}{2} = -1.5$$

Solution Steps

Consider the first equation. Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$6x=-9$$

Divide both sides by 6.

$$x=\frac{-9}{6}$$

Reduce the fraction \frac{-9}{6} to lowest terms by extracting and canceling out 3.

$$x=-\frac{3}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-\frac{3}{2}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-\frac{3}{2}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-\frac{3}{2}$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=-\frac{3}{2}$$

The system is now solved.

$$x=-\frac{3}{2} y=-\frac{3}{2} z=-\frac{3}{2} a=-\frac{3}{2} b=-\frac{3}{2}$$