Solve {l}{590000=x}{y={(x*10/100)}+{(x*12/100*50/100)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 590000 = x }\\ { y = {(x \cdot \frac{10}{100})} + {(x \cdot \frac{12}{100} \cdot \frac{50}{100})} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=94400$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$x=590000$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=590000\times \frac{10}{100}+590000\times \frac{12}{100}\times \frac{50}{100}$$

Reduce the fraction \frac{10}{100} to lowest terms by extracting and canceling out 10.

$$y=590000\times \frac{1}{10}+590000\times \frac{12}{100}\times \frac{50}{100}$$

Multiply 590000 and \frac{1}{10} to get 59000.

$$y=59000+590000\times \frac{12}{100}\times \frac{50}{100}$$

Reduce the fraction \frac{12}{100} to lowest terms by extracting and canceling out 4.

$$y=59000+590000\times \frac{3}{25}\times \frac{50}{100}$$

Multiply 590000 and \frac{3}{25} to get 70800.

$$y=59000+70800\times \frac{50}{100}$$

Reduce the fraction \frac{50}{100} to lowest terms by extracting and canceling out 50.

$$y=59000+70800\times \frac{1}{2}$$

Multiply 70800 and \frac{1}{2} to get 35400.

$$y=59000+35400$$

Add 59000 and 35400 to get 94400.

$$y=94400$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=94400$$

The system is now solved.

$$x=590000 y=94400 z=94400$$