Solve {l}{56x+68x=90}{y=x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 56 x + 68 x = 90 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=\frac{45}{62}\approx 0.725806452$$

Solution Steps

Consider the first equation. Combine 56x and 68x to get 124x.

$$124x=90$$

Divide both sides by 124.

$$x=\frac{90}{124}$$

Reduce the fraction \frac{90}{124} to lowest terms by extracting and canceling out 2.

$$x=\frac{45}{62}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{45}{62}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{45}{62}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=\frac{45}{62}$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=\frac{45}{62}$$

The system is now solved.

$$x=\frac{45}{62} y=\frac{45}{62} z=\frac{45}{62} a=\frac{45}{62} b=\frac{45}{62}$$