Solve for x, y, z
z=0
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52x=100
Consider the first equation. Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
x=\frac{100}{52}
Divide both sides by 52.
x=\frac{25}{13}
Reduce the fraction \frac{100}{52} to lowest terms by extracting and canceling out 4.
x=\frac{25}{13} y=0 z=0
The system is now solved.
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