Solve {l}{5y=55}{26-7y=x}{z=x-6}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 5 y = 55 }\\ { 26 - 7 y = x }\\ { z = x - 6 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, x, z, a

$$a=-57$$

Solution Steps

Consider the first equation. Divide both sides by 5.

$$y=\frac{55}{5}$$

Divide 55 by 5 to get 11.

$$y=11$$

Consider the second equation. Insert the known values of variables into the equation.

$$26-7\times 11=x$$

Multiply -7 and 11 to get -77.

$$26-77=x$$

Subtract 77 from 26 to get -51.

$$-51=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=-51$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-51-6$$

Subtract 6 from -51 to get -57.

$$z=-57$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-57$$

The system is now solved.

$$y=11 x=-51 z=-57 a=-57$$