Solve {l}{5y=5}{{(x+y)}/2=5}{z=3x+0}{a=25}{text{Solvefor}b,ctext{where}}{b=z}{c=a}

$$\left. \begin{array} { l } { 5 y = 5 }\\ { {(x + y)} / 2 = 5 }\\ { z = 3 x + 0 }\\ { a = 25 }\\ { \text{Solve for } b,c \text{ where} } \\ { b = z }\\ { c = a } \end{array} \right.$$

Solve for y, x, z, a, b, c

$$b=27$$

$$c=25$$

Solution Steps

Consider the first equation. Divide both sides by 5.

$$y=\frac{5}{5}$$

Divide 5 by 5 to get 1.

$$y=1$$

Consider the second equation. Insert the known values of variables into the equation.

$$\frac{x+1}{2}=5$$

Multiply both sides by 2.

$$x+1=5\times 2$$

Multiply 5 and 2 to get 10.

$$x+1=10$$

Subtract 1 from both sides.

$$x=10-1$$

Subtract 1 from 10 to get 9.

$$x=9$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=3\times 9+0$$

Multiply 3 and 9 to get 27.

$$z=27+0$$

Add 27 and 0 to get 27.

$$z=27$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=27$$

The system is now solved.

$$y=1 x=9 z=27 a=25 b=27 c=25$$