Solve {l}{5x-40=3x}{y=50x-7}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 5 x - 40 = 3 x }\\ { y = 50 x - 7 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=993$$

Solution Steps

Consider the first equation. Subtract 3x from both sides.

$$5x-40-3x=0$$

Combine 5x and -3x to get 2x.

$$2x-40=0$$

Add 40 to both sides. Anything plus zero gives itself.

$$2x=40$$

Divide both sides by 2.

$$x=\frac{40}{2}$$

Divide 40 by 2 to get 20.

$$x=20$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=50\times 20-7$$

Multiply 50 and 20 to get 1000.

$$y=1000-7$$

Subtract 7 from 1000 to get 993.

$$y=993$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=993$$

The system is now solved.

$$x=20 y=993 z=993$$