Solve {l}{5x-1/8=3}{y={(frac{7*{(5)}+3}{5})}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 5 x - \frac{1}{8} = 3 }\\ { y = {(\frac{7 \cdot {(5)} + 3}{5})} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = \frac{38}{5} = 7\frac{3}{5} = 7.6$$

Solution Steps

Consider the first equation. Add \frac{1}{8} to both sides.

$$5x=3+\frac{1}{8}$$

Add 3 and \frac{1}{8} to get \frac{25}{8}.

$$5x=\frac{25}{8}$$

Divide both sides by 5.

$$x=\frac{\frac{25}{8}}{5}$$

Express \frac{\frac{25}{8}}{5} as a single fraction.

$$x=\frac{25}{8\times 5}$$

Multiply 8 and 5 to get 40.

$$x=\frac{25}{40}$$

Reduce the fraction \frac{25}{40} to lowest terms by extracting and canceling out 5.

$$x=\frac{5}{8}$$

Consider the second equation. Multiply 7 and 5 to get 35.

$$y=\frac{35+3}{5}$$

Add 35 and 3 to get 38.

$$y=\frac{38}{5}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{38}{5}$$

The system is now solved.

$$x=\frac{5}{8} y=\frac{38}{5} z=\frac{38}{5}$$