Solve {l}{5x+6x+2=13}{y=2+x-4}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 5 x + 6 x + 2 = 13 }\\ { y = 2 + x - 4 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-1$$

Solution Steps

Consider the first equation. Combine 5x and 6x to get 11x.

$$11x+2=13$$

Subtract 2 from both sides.

$$11x=13-2$$

Subtract 2 from 13 to get 11.

$$11x=11$$

Divide both sides by 11.

$$x=\frac{11}{11}$$

Divide 11 by 11 to get 1.

$$x=1$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=2+1-4$$

Add 2 and 1 to get 3.

$$y=3-4$$

Subtract 4 from 3 to get -1.

$$y=-1$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-1$$

The system is now solved.

$$x=1 y=-1 z=-1$$