Solve for x, y, z
z=0
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5x+4=0x-4
Consider the first equation. Multiply 0 and 75 to get 0.
5x+4=0-4
Anything times zero gives zero.
5x+4=-4
Subtract 4 from 0 to get -4.
5x=-4-4
Subtract 4 from both sides.
5x=-8
Subtract 4 from -4 to get -8.
x=-\frac{8}{5}
Divide both sides by 5.
x=-\frac{8}{5} y=0 z=0
The system is now solved.
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