Solve {l}{5x+200=4}{y=5x+225}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 5 x + 200 = 4 }\\ { y = 5 x + 225 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=29$$

Solution Steps

Consider the first equation. Subtract 200 from both sides.

$$5x=4-200$$

Subtract 200 from 4 to get -196.

$$5x=-196$$

Divide both sides by 5.

$$x=-\frac{196}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=5\left(-\frac{196}{5}\right)+225$$

Multiply 5 and -\frac{196}{5} to get -196.

$$y=-196+225$$

Add -196 and 225 to get 29.

$$y=29$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=29$$

The system is now solved.

$$x=-\frac{196}{5} y=29 z=29$$