Solve {l}{5x+2=y}{y=4}{z=5x+3}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 5 x + 2 = y }\\ { y = 4 }\\ { z = 5 x + 3 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=5$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$5x+2=4$$

Subtract 2 from both sides.

$$5x=4-2$$

Subtract 2 from 4 to get 2.

$$5x=2$$

Divide both sides by 5.

$$x=\frac{2}{5}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=5\times \frac{2}{5}+3$$

Multiply 5 and \frac{2}{5} to get 2.

$$z=2+3$$

Add 2 and 3 to get 5.

$$z=5$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=5$$

The system is now solved.

$$x=\frac{2}{5} y=4 z=5 a=5$$