Solve {l}{5x+11=4-3x}{y=0*0}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 5 x + 11 = 4 - 3 x }\\ { y = 0 \cdot 0 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=0$$

Solution Steps

Consider the first equation. Add 3x to both sides.

$$5x+11+3x=4$$

Combine 5x and 3x to get 8x.

$$8x+11=4$$

Subtract 11 from both sides.

$$8x=4-11$$

Subtract 11 from 4 to get -7.

$$8x=-7$$

Divide both sides by 8.

$$x=-\frac{7}{8}$$

Consider the second equation. Multiply 0 and 0 to get 0.

$$y=0$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=0$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=0$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=0$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=0$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=0$$

The system is now solved.

$$x=-\frac{7}{8} y=0 z=0 a=0 b=0 c=0 d=0$$