Solve {l}{5j+3=2j+21}{k=22}{l=k}{m=l}{n=m}{o=n}{p=o}{q=p}{r=q}{text{Solvefor}stext{where}}{s=r}

$$\left. \begin{array} { l } { 5 j + 3 = 2 j + 21 }\\ { k = 22 }\\ { l = k }\\ { m = l }\\ { n = m }\\ { o = n }\\ { p = o }\\ { q = p }\\ { r = q }\\ { \text{Solve for } s \text{ where} } \\ { s = r } \end{array} \right.$$

Solve for j, k, l, m, n, o, p, q, r, s

$$s=22$$

Solution Steps

Consider the first equation. Subtract 2j from both sides.

$$5j+3-2j=21$$

Combine 5j and -2j to get 3j.

$$3j+3=21$$

Subtract 3 from both sides.

$$3j=21-3$$

Subtract 3 from 21 to get 18.

$$3j=18$$

Divide both sides by 3.

$$j=\frac{18}{3}$$

Divide 18 by 3 to get 6.

$$j=6$$

The system is now solved.

$$j=6 k=22 l=22 m=22 n=22 o=22 p=22 q=22 r=22 s=22$$