Solve for b, c, d
d=4
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2b-\left(4\times 7+1\times 3\right)=12
Consider the first equation. Combine 5b and -3b to get 2b.
2b-\left(28+3\right)=12
Do the multiplications.
2b-31=12
Add 28 and 3 to get 31.
2b=12+31
Add 31 to both sides.
2b=43
Add 12 and 31 to get 43.
b=\frac{43}{2}
Divide both sides by 2.
b=\frac{43}{2} c=4 d=4
The system is now solved.
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