Solve for y, z, a
a=282
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405-5y+372\times 5y=28512
Consider the first equation. Use the distributive property to multiply 5 by 81-y.
405-5y+1860y=28512
Multiply 372 and 5 to get 1860.
405+1855y=28512
Combine -5y and 1860y to get 1855y.
1855y=28512-405
Subtract 405 from both sides.
1855y=28107
Subtract 405 from 28512 to get 28107.
y=\frac{28107}{1855}
Divide both sides by 1855.
y=\frac{28107}{1855} z=282 a=282
The system is now solved.
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