Solve {l}{5{(4a+8)}=9-2a}{b=3+0}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 5 {(4 a + 8)} = 9 - 2 a }\\ { b = 3 + 0 }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for a, b, c, d

$$d=3$$

Solution Steps

Consider the first equation. Use the distributive property to multiply 5 by 4a+8.

$$20a+40=9-2a$$

Add 2a to both sides.

$$20a+40+2a=9$$

Combine 20a and 2a to get 22a.

$$22a+40=9$$

Subtract 40 from both sides.

$$22a=9-40$$

Subtract 40 from 9 to get -31.

$$22a=-31$$

Divide both sides by 22.

$$a=-\frac{31}{22}$$

Consider the second equation. Add 3 and 0 to get 3.

$$b=3$$

Consider the third equation. Insert the known values of variables into the equation.

$$c=3$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$d=3$$

The system is now solved.

$$a=-\frac{31}{22} b=3 c=3 d=3$$