Solve {l}{5{(2-4x)}=3-x}{y=0}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 5 {(2 - 4 x)} = 3 - x }\\ { y = 0 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=0$$

Solution Steps

Consider the first equation. Use the distributive property to multiply 5 by 2-4x.

$$10-20x=3-x$$

Add x to both sides.

$$10-20x+x=3$$

Combine -20x and x to get -19x.

$$10-19x=3$$

Subtract 10 from both sides.

$$-19x=3-10$$

Subtract 10 from 3 to get -7.

$$-19x=-7$$

Divide both sides by -19.

$$x=\frac{-7}{-19}$$

Fraction \frac{-7}{-19} can be simplified to \frac{7}{19} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{7}{19}$$

The system is now solved.

$$x=\frac{7}{19} y=0 z=0$$