Solve for x, y, z
z=1
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40=15x
Consider the first equation. Multiply 5 and 8 to get 40.
15x=40
Swap sides so that all variable terms are on the left hand side.
x=\frac{40}{15}
Divide both sides by 15.
x=\frac{8}{3}
Reduce the fraction \frac{40}{15} to lowest terms by extracting and canceling out 5.
x=\frac{8}{3} y=1 z=1
The system is now solved.
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