Solve {l}{5*3={(frac{1*{(3)}+1}{3})}/x}{y=0}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 5 \cdot 3 = {(\frac{1 \cdot {(3)} + 1}{3})} / x }\\ { y = 0 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=0$$

Solution Steps

Consider the first equation. Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$5\times 3x=\frac{1\times 3+1}{3}$$

Multiply 5 and 3 to get 15.

$$15x=\frac{1\times 3+1}{3}$$

Multiply 1 and 3 to get 3.

$$15x=\frac{3+1}{3}$$

Add 3 and 1 to get 4.

$$15x=\frac{4}{3}$$

Divide both sides by 15.

$$x=\frac{\frac{4}{3}}{15}$$

Express \frac{\frac{4}{3}}{15} as a single fraction.

$$x=\frac{4}{3\times 15}$$

Multiply 3 and 15 to get 45.

$$x=\frac{4}{45}$$

The system is now solved.

$$x=\frac{4}{45} y=0 z=0$$