Solve {l}{5*{(2-3u)}=0*3*{(5*4n)}+4}{v=0}{text{Solvefor}wtext{where}}{w=v}

$$\left. \begin{array} { l } { 5 \cdot {(2 - 3 u)} = 0 \cdot 3 \cdot {(5 \cdot 4 n)} + 4 }\\ { v = 0 }\\ { \text{Solve for } w \text{ where} } \\ { w = v } \end{array} \right.$$

Solve for u, n, v, w

$$w=0$$

Solution Steps

Consider the first equation. Use the distributive property to multiply 5 by 2-3u.

$$10-15u=0\times 3\times 5\times 4n+4$$

Multiply 0 and 3 to get 0.

$$10-15u=0\times 5\times 4n+4$$

Multiply 0 and 5 to get 0.

$$10-15u=0\times 4n+4$$

Multiply 0 and 4 to get 0.

$$10-15u=0n+4$$

Anything times zero gives zero.

$$10-15u=0+4$$

Add 0 and 4 to get 4.

$$10-15u=4$$

Subtract 10 from both sides.

$$-15u=4-10$$

Subtract 10 from 4 to get -6.

$$-15u=-6$$

Divide both sides by -15.

$$u=\frac{-6}{-15}$$

Reduce the fraction \frac{-6}{-15} to lowest terms by extracting and canceling out -3.

$$u=\frac{2}{5}$$

The system is now solved.

$$u=\frac{2}{5} v=0 w=0$$