Solve for y, z, a
a=5
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5\left(4+3y\right)+8y=-2
Consider the first equation. Multiply both sides of the equation by 2.
20+15y+8y=-2
Use the distributive property to multiply 5 by 4+3y.
20+23y=-2
Combine 15y and 8y to get 23y.
23y=-2-20
Subtract 20 from both sides.
23y=-22
Subtract 20 from -2 to get -22.
y=-\frac{22}{23}
Divide both sides by 23.
y=-\frac{22}{23} z=5 a=5
The system is now solved.
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