Solve {l}{5=x}{y=32*48}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 5 = x }\\ { y = 32 \cdot 48 }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=1536$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$x=5$$

Consider the second equation. Multiply 32 and 48 to get 1536.

$$y=1536$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=1536$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=1536$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=1536$$

The system is now solved.

$$x=5 y=1536 z=1536 a=1536 b=1536$$