Solve {l}{49.4-36.88=0.313x}{y=0.313x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 49.4 - 36.88 = 0.313 x }\\ { y = 0.313 x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=12.52$$

Solution Steps

Consider the first equation. Subtract 36.88 from 49.4 to get 12.52.

$$12.52=0.313x$$

Swap sides so that all variable terms are on the left hand side.

$$0.313x=12.52$$

Divide both sides by 0.313.

$$x=\frac{12.52}{0.313}$$

Expand \frac{12.52}{0.313} by multiplying both numerator and the denominator by 1000.

$$x=\frac{12520}{313}$$

Divide 12520 by 313 to get 40.

$$x=40$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=0.313\times 40$$

Multiply 0.313 and 40 to get 12.52.

$$y=12.52$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=12.52$$

The system is now solved.

$$x=40 y=12.52 z=12.52$$