Solve {l}{45x=12/32}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 45 x = \frac{12}{32} }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=\frac{1}{120}\approx 0.008333333$$

Solution Steps

Consider the first equation. Reduce the fraction \frac{12}{32} to lowest terms by extracting and canceling out 4.

$$45x=\frac{3}{8}$$

Divide both sides by 45.

$$x=\frac{\frac{3}{8}}{45}$$

Express \frac{\frac{3}{8}}{45} as a single fraction.

$$x=\frac{3}{8\times 45}$$

Multiply 8 and 45 to get 360.

$$x=\frac{3}{360}$$

Reduce the fraction \frac{3}{360} to lowest terms by extracting and canceling out 3.

$$x=\frac{1}{120}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{1}{120}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{1}{120}$$

The system is now solved.

$$x=\frac{1}{120} y=\frac{1}{120} z=\frac{1}{120}$$