Solve {l}{45x+4.5x=44x+7.70}{y=0*0*0}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 45 x + 4.5 x = 44 x + 7.70 }\\ { y = 0 \cdot 0 \cdot 0 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=0$$

Solution Steps

Consider the first equation. Combine 45x and 4.5x to get 49.5x.

$$49.5x=44x+7.7$$

Subtract 44x from both sides.

$$49.5x-44x=7.7$$

Combine 49.5x and -44x to get 5.5x.

$$5.5x=7.7$$

Divide both sides by 5.5.

$$x=\frac{7.7}{5.5}$$

Expand \frac{7.7}{5.5} by multiplying both numerator and the denominator by 10.

$$x=\frac{77}{55}$$

Reduce the fraction \frac{77}{55} to lowest terms by extracting and canceling out 11.

$$x=\frac{7}{5}$$

Consider the second equation. Multiply 0 and 0 to get 0.

$$y=0\times 0$$

Multiply 0 and 0 to get 0.

$$y=0$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=0$$

The system is now solved.

$$x=\frac{7}{5} y=0 z=0$$