Solve {l}{42=5x*108/360}{y=9}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 42 = 5 x \cdot \frac{108}{360} }\\ { y = 9 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=9$$

Solution Steps

Consider the first equation. Reduce the fraction \frac{108}{360} to lowest terms by extracting and canceling out 36.

$$42=5x\times \frac{3}{10}$$

Multiply 5 and \frac{3}{10} to get \frac{3}{2}.

$$42=\frac{3}{2}x$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{2}x=42$$

Multiply both sides by \frac{2}{3}, the reciprocal of \frac{3}{2}.

$$x=42\times \frac{2}{3}$$

Multiply 42 and \frac{2}{3} to get 28.

$$x=28$$

The system is now solved.

$$x=28 y=9 z=9$$