Solve {l}{4x-3=25}{y=x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 4 x - 3 = 25 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=7$$

Solution Steps

Consider the first equation. Add 3 to both sides.

$$4x=25+3$$

Add 25 and 3 to get 28.

$$4x=28$$

Divide both sides by 4.

$$x=\frac{28}{4}$$

Divide 28 by 4 to get 7.

$$x=7$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=7$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=7$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=7$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=7$$

The system is now solved.

$$x=7 y=7 z=7 a=7 b=7$$