Solve {l}{4x-12=0}{y=4x+12}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 4 x - 12 = 0 }\\ { y = 4 x + 12 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c=24$$

Solution Steps

Consider the first equation. Add 12 to both sides. Anything plus zero gives itself.

$$4x=12$$

Divide both sides by 4.

$$x=\frac{12}{4}$$

Divide 12 by 4 to get 3.

$$x=3$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=4\times 3+12$$

Multiply 4 and 3 to get 12.

$$y=12+12$$

Add 12 and 12 to get 24.

$$y=24$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=24$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=24$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=24$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=24$$

The system is now solved.

$$x=3 y=24 z=24 a=24 b=24 c=24$$