Solve {l}{4x=31}{y=34+25}{z=-3*4}{text{Solvefor}a,btext{where}}{a=y}{b=z}

$$\left. \begin{array} { l } { 4 x = 31 }\\ { y = 34 + 25 }\\ { z = -3 \cdot 4 }\\ { \text{Solve for } a,b \text{ where} } \\ { a = y }\\ { b = z } \end{array} \right.$$

Solve for x, y, z, a, b

$$a=59$$

$$b=-12$$

Solution Steps

Consider the first equation. Divide both sides by 4.

$$x=\frac{31}{4}$$

Consider the second equation. Add 34 and 25 to get 59.

$$y=59$$

Consider the third equation. Multiply -3 and 4 to get -12.

$$z=-12$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=59$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=-12$$

The system is now solved.

$$x=\frac{31}{4} y=59 z=-12 a=59 b=-12$$