Solve for x, y, z
x=-\frac{3a}{4}+3
y=a
z=a
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z=y 4x+3y=12 a=z
Reorder the equations.
a=y
Substitute y for z in the equation a=z.
x=3-\frac{3}{4}y y=a
Solve the second equation for x and the third equation for y.
x=3-\frac{3}{4}a
Substitute a for y in the equation x=3-\frac{3}{4}y.
z=a
Substitute a for y in the equation z=y.
x=3-\frac{3}{4}a y=a z=a
The system is now solved.
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