Solve {l}{4k+12=62}{5y=7}{l=5-2}{m=5}{text{Solvefor}n,otext{where}}{n=l}{o=m}

$$\left. \begin{array} { l } { 4 k + 12 = 62 }\\ { 5 y = 7 }\\ { l = 5 - 2 }\\ { m = 5 }\\ { \text{Solve for } n,o \text{ where} } \\ { n = l }\\ { o = m } \end{array} \right.$$

Solve for k, y, l, m, n, o

$$n=3$$

$$o=5$$

Solution Steps

Consider the first equation. Subtract 12 from both sides.

$$4k=62-12$$

Subtract 12 from 62 to get 50.

$$4k=50$$

Divide both sides by 4.

$$k=\frac{50}{4}$$

Reduce the fraction \frac{50}{4} to lowest terms by extracting and canceling out 2.

$$k=\frac{25}{2}$$

Consider the second equation. Divide both sides by 5.

$$y=\frac{7}{5}$$

Consider the third equation. Subtract 2 from 5 to get 3.

$$l=3$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$n=3$$

The system is now solved.

$$k=\frac{25}{2} y=\frac{7}{5} l=3 m=5 n=3 o=5$$