Solve {l}{4b-1=b}{c=24b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 4 b - 1 = b }\\ { c = 24 b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for b, c, d

$$d=8$$

Solution Steps

Consider the first equation. Subtract b from both sides.

$$4b-1-b=0$$

Combine 4b and -b to get 3b.

$$3b-1=0$$

Add 1 to both sides. Anything plus zero gives itself.

$$3b=1$$

Divide both sides by 3.

$$b=\frac{1}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$c=24\times \frac{1}{3}$$

Multiply 24 and \frac{1}{3} to get 8.

$$c=8$$

Consider the third equation. Insert the known values of variables into the equation.

$$d=8$$

The system is now solved.

$$b=\frac{1}{3} c=8 d=8$$