Solve {l}{4{(x-1)}=10}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 4 {(x - 1)} = 10 }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = \frac{7}{2} = 3\frac{1}{2} = 3.5$$

Solution Steps

Consider the first equation. Divide both sides by 4.

$$x-1=\frac{10}{4}$$

Reduce the fraction \frac{10}{4} to lowest terms by extracting and canceling out 2.

$$x-1=\frac{5}{2}$$

Add 1 to both sides.

$$x=\frac{5}{2}+1$$

Add \frac{5}{2} and 1 to get \frac{7}{2}.

$$x=\frac{7}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{7}{2}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{7}{2}$$

The system is now solved.

$$x=\frac{7}{2} y=\frac{7}{2} z=\frac{7}{2}$$