Solve {l}{4{(9-x)}=52}{y=x}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 4 {(9 - x)} = 52 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c=-4$$

Solution Steps

Consider the first equation. Divide both sides by 4.

$$9-x=\frac{52}{4}$$

Divide 52 by 4 to get 13.

$$9-x=13$$

Subtract 9 from both sides.

$$-x=13-9$$

Subtract 9 from 13 to get 4.

$$-x=4$$

Divide both sides by -1.

$$x=-4$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-4$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-4$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-4$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=-4$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=-4$$

The system is now solved.

$$x=-4 y=-4 z=-4 a=-4 b=-4 c=-4$$