Solve {l}{36=5Q+1}{a=Q}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 36 = 5 Q + 1 }\\ { a = Q }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for Q, a, b, c, d

$$d=7$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$5Q+1=36$$

Subtract 1 from both sides.

$$5Q=36-1$$

Subtract 1 from 36 to get 35.

$$5Q=35$$

Divide both sides by 5.

$$Q=\frac{35}{5}$$

Divide 35 by 5 to get 7.

$$Q=7$$

Consider the second equation. Insert the known values of variables into the equation.

$$a=7$$

Consider the third equation. Insert the known values of variables into the equation.

$$b=7$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$c=7$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$d=7$$

The system is now solved.

$$Q=7 a=7 b=7 c=7 d=7$$