Solve {l}{35x+3=y}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 35 x + 3 = y }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z

$$x=\frac{a-3}{35}$$

$$y=a$$

$$z=a$$

Short Steps Using Substitution

Solve 35x+3=y for y.

$$y=35x+3$$

Substitute 35x+3 for y in the equation z=y.

$$z=35x+3$$

Solve the second equation for x and the third equation for z.

$$x=-\frac{3}{35}+\frac{1}{35}z z=a$$

Substitute a for z in the equation x=-\frac{3}{35}+\frac{1}{35}z.

$$x=-\frac{3}{35}+\frac{1}{35}a$$

Substitute -\frac{3}{35}+\frac{1}{35}a for x in the equation y=35x+3.

$$y=35\left(-\frac{3}{35}+\frac{1}{35}a\right)+3$$

Calculate y from y=35\left(-\frac{3}{35}+\frac{1}{35}a\right)+3.

$$y=a$$

The system is now solved.

$$x=-\frac{3}{35}+\frac{1}{35}a y=a z=a$$