Solve {l}{30625*0+5/100x=x}{y=1}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 30625 \cdot 0 + \frac{5}{100} x = x }\\ { y = 1 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=1$$

Solution Steps

Consider the first equation. Multiply 30625 and 0 to get 0.

$$0+\frac{5}{100}x=x$$

Reduce the fraction \frac{5}{100} to lowest terms by extracting and canceling out 5.

$$0+\frac{1}{20}x=x$$

Anything plus zero gives itself.

$$\frac{1}{20}x=x$$

Subtract x from both sides.

$$\frac{1}{20}x-x=0$$

Combine \frac{1}{20}x and -x to get -\frac{19}{20}x.

$$-\frac{19}{20}x=0$$

Multiply both sides by -\frac{20}{19}, the reciprocal of -\frac{19}{20}. Anything times zero gives zero.

$$x=0$$

The system is now solved.

$$x=0 y=1 z=1$$