Solve {l}{3000-x*360=2*100*35.64}{y={(1+x)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 3000 - x \cdot 360 = 2 \cdot 100 \cdot 35.64 }\\ { y = {(1 + x)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = -\frac{157}{15} = -10\frac{7}{15} \approx -10.466666667$$

Solution Steps

Consider the first equation. Multiply 2 and 100 to get 200.

$$3000-x\times 360=200\times 35.64$$

Multiply 200 and 35.64 to get 7128.

$$3000-x\times 360=7128$$

Multiply -1 and 360 to get -360.

$$3000-360x=7128$$

Subtract 3000 from both sides.

$$-360x=7128-3000$$

Subtract 3000 from 7128 to get 4128.

$$-360x=4128$$

Divide both sides by -360.

$$x=\frac{4128}{-360}$$

Reduce the fraction \frac{4128}{-360} to lowest terms by extracting and canceling out 24.

$$x=-\frac{172}{15}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=1-\frac{172}{15}$$

Subtract \frac{172}{15} from 1 to get -\frac{157}{15}.

$$y=-\frac{157}{15}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-\frac{157}{15}$$

The system is now solved.

$$x=-\frac{172}{15} y=-\frac{157}{15} z=-\frac{157}{15}$$