Solve {l}{3x-2{(0*7+20)}=3*6-1*7x}{y=2}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 3 x - 2 {(0 \cdot 7 + 20)} = 3 \cdot 6 - 1 \cdot 7 x }\\ { y = 2 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c=2$$

Solution Steps

Consider the first equation. Multiply 0 and 7 to get 0.

$$3x-2\left(0+20\right)=3\times 6-1\times 7x$$

Add 0 and 20 to get 20.

$$3x-2\times 20=3\times 6-1\times 7x$$

Multiply 2 and 20 to get 40.

$$3x-40=3\times 6-1\times 7x$$

Multiply 3 and 6 to get 18.

$$3x-40=18-1\times 7x$$

Multiply 1 and 7 to get 7.

$$3x-40=18-7x$$

Add 7x to both sides.

$$3x-40+7x=18$$

Combine 3x and 7x to get 10x.

$$10x-40=18$$

Add 40 to both sides.

$$10x=18+40$$

Add 18 and 40 to get 58.

$$10x=58$$

Divide both sides by 10.

$$x=\frac{58}{10}$$

Reduce the fraction \frac{58}{10} to lowest terms by extracting and canceling out 2.

$$x=\frac{29}{5}$$

The system is now solved.

$$x=\frac{29}{5} y=2 z=2 a=2 b=2 c=2$$