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Solve for x, y, z
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3x-2\left(0+20\right)=3\times 6-1\times 7x
Consider the first equation. Multiply 0 and 7 to get 0.
3x-2\times 20=3\times 6-1\times 7x
Add 0 and 20 to get 20.
3x-40=3\times 6-1\times 7x
Multiply 2 and 20 to get 40.
3x-40=18-1\times 7x
Multiply 3 and 6 to get 18.
3x-40=18-7x
Multiply 1 and 7 to get 7.
3x-40+7x=18
Add 7x to both sides.
10x-40=18
Combine 3x and 7x to get 10x.
10x=18+40
Add 40 to both sides.
10x=58
Add 18 and 40 to get 58.
x=\frac{58}{10}
Divide both sides by 10.
x=\frac{29}{5}
Reduce the fraction \frac{58}{10} to lowest terms by extracting and canceling out 2.
x=\frac{29}{5} y=2 z=2
The system is now solved.