Solve {l}{3x=18}{3y=9}{2z-z=6}{a=y*x-z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 3 x = 18 }\\ { 3 y = 9 }\\ { 2 z - z = 6 }\\ { a = y \cdot x - z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=12$$

Solution Steps

Consider the first equation. Divide both sides by 3.

$$x=\frac{18}{3}$$

Divide 18 by 3 to get 6.

$$x=6$$

Consider the second equation. Divide both sides by 3.

$$y=\frac{9}{3}$$

Divide 9 by 3 to get 3.

$$y=3$$

Consider the third equation. Combine 2z and -z to get z.

$$z=6$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=3\times 6-6$$

Do the multiplications.

$$a=18-6$$

Subtract 6 from 18 to get 12.

$$a=12$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=12$$

The system is now solved.

$$x=6 y=3 z=6 a=12 b=12$$