Solve for x, y, z
x=\frac{1-8a}{3}
y=a
z=a
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z=y 3x+8y=1 a=z
Reorder the equations.
a=y
Substitute y for z in the equation a=z.
x=-\frac{8}{3}y+\frac{1}{3} y=a
Solve the second equation for x and the third equation for y.
x=-\frac{8}{3}a+\frac{1}{3}
Substitute a for y in the equation x=-\frac{8}{3}y+\frac{1}{3}.
z=a
Substitute a for y in the equation z=y.
x=-\frac{8}{3}a+\frac{1}{3} y=a z=a
The system is now solved.
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