Solve {l}{3x+5=100}{y=x}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 3 x + 5 = 100 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c = \frac{95}{3} = 31\frac{2}{3} \approx 31.666666667$$

Solution Steps

Consider the first equation. Subtract 5 from both sides.

$$3x=100-5$$

Subtract 5 from 100 to get 95.

$$3x=95$$

Divide both sides by 3.

$$x=\frac{95}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{95}{3}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{95}{3}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=\frac{95}{3}$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=\frac{95}{3}$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=\frac{95}{3}$$

The system is now solved.

$$x=\frac{95}{3} y=\frac{95}{3} z=\frac{95}{3} a=\frac{95}{3} b=\frac{95}{3} c=\frac{95}{3}$$