Solve for a, b, c
c=1
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3a+24=9
Consider the first equation. Multiply 4 and 6 to get 24.
3a=9-24
Subtract 24 from both sides.
3a=-15
Subtract 24 from 9 to get -15.
a=\frac{-15}{3}
Divide both sides by 3.
a=-5
Divide -15 by 3 to get -5.
a=-5 b=1 c=1
The system is now solved.
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